22x^2-125x+22=0

Solution for 22x^2-125x+22=0 equation:

22x^2-125x+22=0

a = 22; b = -125; c = +22;
Δ = b2-4ac
Δ = -1252-4·22·22
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13689}=117$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-125)-117}{2*22}=\frac{8}{44}
=2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-125)+117}{2*22}=\frac{242}{44}
=5+1/2
$